0=3x^2+25x-18

Solution for 0=3x^2+25x-18 equation:

0=3x^2+25x-18

We move all terms to the left:

0-(3x^2+25x-18)=0

We add all the numbers together, and all the variables

-(3x^2+25x-18)=0

We get rid of parentheses

-3x^2-25x+18=0

a = -3; b = -25; c = +18;
Δ = b2-4ac
Δ = -252-4·(-3)·18
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-29}{2*-3}=\frac{-4}{-6}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+29}{2*-3}=\frac{54}{-6}
=-9
$